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Configuration = 87
cycles = (10 6 1 9 3)(8 5 2 7 4)

a = 1, b = 3, c = 6
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cycles = (10 6)(9 1)(8 3 5 7 2)(4)

a = 3, b = 5, c = 8
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cycles = (10 4)(9 1)(8 5 2)(7)(6)(3)

a = 4, b = 9, c = 10
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cycles = (10 1 4)(9 6 2)(8)(7)(5)(3)

a = 1, b = 4, c = 10
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cycles = (10)(9)(8 6 3)(7)(5)(4)(2)(1)